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[JS] ๋ฐฑ์ค€ 8393๋ฒˆ : ํ•ฉ
Algorithms/Baekjoon

[JS] ๋ฐฑ์ค€ 8393๋ฒˆ : ํ•ฉ

2022. 4. 12. 23:56
๋ฐ˜์‘ํ˜•

 

Question

 

๋ฐฑ์ค€ 8393๋ฒˆ : ํ•ฉ

n์ด ์ฃผ์–ด์กŒ์„ ๋•Œ, 1๋ถ€ํ„ฐ n๊นŒ์ง€ ํ•ฉ์„ ๊ตฌํ•˜๋Š” ํ”„๋กœ๊ทธ๋žจ์„ ์ž‘์„ฑํ•˜์‹œ์˜ค.

 

8393๋ฒˆ: ํ•ฉ

n์ด ์ฃผ์–ด์กŒ์„ ๋•Œ, 1๋ถ€ํ„ฐ n๊นŒ์ง€ ํ•ฉ์„ ๊ตฌํ•˜๋Š” ํ”„๋กœ๊ทธ๋žจ์„ ์ž‘์„ฑํ•˜์‹œ์˜ค.

www.acmicpc.net

 


 

My Code

let input = require('fs').readFileSync('dev/stdin').toString().split('\n');

let num = Number(input[0]);
let sum = 0;
for (let i = 1; i <= num ; i ++ ) {
    sum += i;
}
console.log(sum);

 

๋งž์•˜์Šต๋‹ˆ๋‹ค!!

 

 

HOW?

 

1. ๋ณ€์ˆ˜ sum์„ ์„ ์–ธํ•ด 0์„ ํ• ๋‹นํ•œ๋‹ค.

2. ์ฃผ์–ด์ง„ n๋งŒํผ for ๋ฌธ์„ ๋Œ๋ฆฌ๋ฉด์„œ sum์— ๊ฐ’์„ ๋”ํ•ด๊ฐ„๋‹ค.

 

 

 

์ˆœ๊ฐ„ for๋ฌธ์„ ์–ด๋–ป๊ฒŒ ๋Œ๋ฆฌ๋Š” ๊ฑฐ์˜€์ง€. ๋จธ๋ฆฌ๊ฐ€ ์•ˆ ๋Œ์•„๊ฐ€์„œ ํ ์นซํ–ˆ๋‹ค. ๋ชจ๋‹ˆํ„ฐ๋ฅผ ์˜ค๋ž˜ ๋ณด๊ณ  ์žˆ๋Š”๋‹ค๊ณ  ๋ฌด์กฐ๊ฑด ๊ณต๋ถ€๊ฐ€ ๋Š˜์–ด๊ฐ€๋Š” ๊ฒŒ ์•„๋‹Œ ๊ฑฐ ๊ฐ™๋‹ค. ์ค‘๊ฐ„์ค‘๊ฐ„ ํ™˜๊ธฐ๋„ ํ•ด์ฃผ๋ฉด์„œ ๋ฌธ์ œ๋ฅผ ํ’€์–ด๊ฐ€์•ผ๊ฒ ๋‹ค. ๊ณต๋ถ€ํ• ๊ฒŒ ๋งŽ์•„์„œ ํ–‰๋ณตํ•˜๋‹ค. ํ”„๋ก ํŠธ์—”๋“œ ๊ฐœ๋ฐœ์ž๊ฐ€ ๋˜๋Š” ๋‚ ๊นŒ์ง€ ๋‹ฌ๋ ค!

๋ฐ˜์‘ํ˜•
์ €์ž‘์žํ‘œ์‹œ ๋น„์˜๋ฆฌ ๋ณ€๊ฒฝ๊ธˆ์ง€ (์ƒˆ์ฐฝ์—ด๋ฆผ)

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